What is the inverse of f(x)=100x^2+7,x>= 0 ?

The inverse of f(x)=100x^2+7,x>= 0 is (sqrt(x-7))/(10),-(sqrt(x-7))/(10)

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inverse of f(x)=100x^2+7,x>= 0

inverse

f (x) = 100 x^{2} + 7, x \geq 0

\frac{x - 7}{10}, - \frac{x - 7}{10}

Solution steps

y = 100 x^{2} + 7

Replace

x

with

y

x = 100 y^{2} + 7

Solve for

y, x = 100 y^{2} + 7

\frac{x - 7}{10}, - \frac{x - 7}{10}

f (x) = \frac{6 x}{7}

f (x) = \frac{6 x}{x - 7}

f (x) = x^{2} - 3 x + 8

f (x) = 4 x + 40

f (x) = - 8 x^{2} + 4 x

What is the inverse of f(x)=100x^2+7,x>= 0 ?
The inverse of f(x)=100x^2+7,x>= 0 is (sqrt(x-7))/(10),-(sqrt(x-7))/(10)