What is the inverse of f(x)=x^2-3x+8 ?

The inverse of f(x)=x^2-3x+8 is (3+sqrt(4x-23))/2 ,(3-sqrt(4x-23))/2

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inverse of f(x)=x^2-3x+8

inverse

f (x) = x^{2} - 3 x + 8

\frac{3 + 4 x - 23}{2}, \frac{3 - 4 x - 23}{2}

Solution steps

y = x^{2} - 3 x + 8

Replace

x

with

y

x = y^{2} - 3 y + 8

Solve for

y, x = y^{2} - 3 y + 8

\frac{3 + 4 x - 23}{2}, \frac{3 - 4 x - 23}{2}

f (x) = 4 x + 40

f (x) = - 8 x^{2} + 4 x

f (x) = \frac{6 x}{x - 5}

f (x) = 4 x + 19

\frac{1}{6} x^{3} - 3

What is the inverse of f(x)=x^2-3x+8 ?
The inverse of f(x)=x^2-3x+8 is (3+sqrt(4x-23))/2 ,(3-sqrt(4x-23))/2