What is the inverse of f(x)=x^2-2x+2,x<= 1 ?

The inverse of f(x)=x^2-2x+2,x<= 1 is 1+sqrt(x-1),1-sqrt(x-1)

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inverse of f(x)=x^2-2x+2,x<= 1

inverse

f (x) = x^{2} - 2 x + 2, x \leq 1

1 + x - 1, 1 - x - 1

Solution steps

y = x^{2} - 2 x + 2

Replace

x

with

y

x = y^{2} - 2 y + 2

Solve for

y, x = y^{2} - 2 y + 2

1 + x - 1, 1 - x - 1

f (x) = 18500 (0.25 - r^{2})

f (x) = ln (7 x + 4) - 2

f (x) = 9 x^{3} - 6

f (x) = - 7 cos (2 x)

f (x) = 2 π r^{2} + 2 π r 8

What is the inverse of f(x)=x^2-2x+2,x<= 1 ?
The inverse of f(x)=x^2-2x+2,x<= 1 is 1+sqrt(x-1),1-sqrt(x-1)