What is the inverse of f(x)=arccos(x^2) ?

The inverse of f(x)=arccos(x^2) is sqrt(cos(x)),-sqrt(cos(x))

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inverse of f(x)=arccos(x^2)

inverse

f (x) = arccos (x^{2})

cos (x), - cos (x)

Solution steps

arccos (a) = b \Rightarrow a = cos (b)

x^{2} = cos (y)

Solve for

x, x^{2} = cos (y)

cos (y), - cos (y)

Substitute

y = x

cos (x), - cos (x)

2 x - 3 + 5

f (x) = \frac{( - 2 x - 1 )}{x + 5}

\frac{8 x + 9}{5 x - 8}

\frac{e ^{x - 3}}{4}

+ 0.52 cos (\frac{2 π}{11.608} x) + 0.37

What is the inverse of f(x)=arccos(x^2) ?
The inverse of f(x)=arccos(x^2) is sqrt(cos(x)),-sqrt(cos(x))