What is the inverse of+0.52cos((2pi)/(11.608)x)+0.37 ?

The inverse of+0.52cos((2pi)/(11.608)x)+0.37 is 1.84747…arccos((100x-37)/(52))

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inverse of+0.52cos((2pi)/(11.608)x)+0.37

inverse

+ 0.52 cos (\frac{2 π}{11.608} x) + 0.37

1.84747 \dots arccos (\frac{100 x - 37}{52})

Solution steps

Solve for

cos (\frac{2 π}{11.608} x), y = + 0.52 cos (\frac{2 π}{11.608} x) + 0.37

cos (\frac{2 π}{11.608} x) = \frac{100 y - 37}{52}

cos (a) = b \Rightarrow a = arccos (b)

\frac{2 π}{11.608} x = arccos (\frac{100 y - 37}{52})

Solve for

x, \frac{2 π}{11.608} x = arccos (\frac{100 y - 37}{52})

1.84747 \dots arccos (\frac{100 y - 37}{52})

Substitute

y = x

1.84747 \dots arccos (\frac{100 x - 37}{52})

x^{4} + x^{2} + 16

x^{2 l n (x)}

f (x) = \frac{2 x - 3}{7 x + 9}

f (x) = (2 x - 9)

f (x) = 8 x^{2} - 3

What is the inverse of+0.52cos((2pi)/(11.608)x)+0.37 ?
The inverse of+0.52cos((2pi)/(11.608)x)+0.37 is 1.84747…arccos((100x-37)/(52))