What is the inverse of (x^2-16)/(x^2-x-6) ?

The inverse of (x^2-16)/(x^2-x-6) is (x+sqrt(25x^2-88x+64))/(2(x-1)),(x-sqrt(25x^2-88x+64))/(2(x-1))

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inverse of (x^2-16)/(x^2-x-6)

inverse

\frac{x ^{2} - 16}{x ^{2} - x - 6}

\frac{x + 25 x ^{2} - 88 x + 64}{2 ( x - 1 )}, \frac{x - 25 x ^{2} - 88 x + 64}{2 ( x - 1 )}

Solution steps

y = \frac{x ^{2} - 16}{x ^{2} - x - 6}

Replace

x

with

y

x = \frac{y ^{2} - 16}{y ^{2} - y - 6}

Solve for

y, x = \frac{y ^{2} - 16}{y ^{2} - y - 6}

\frac{x + 25 x ^{2} - 88 x + 64}{2 ( x - 1 )}, \frac{x - 25 x ^{2} - 88 x + 64}{2 ( x - 1 )}

f (x) = 5 e^{2 x - 1}

f (x) = \frac{- 4 x}{- x + 3}

4 + 6 x

4 cos^{2} (x)

\frac{4 x - 1}{2 x + 1}

What is the inverse of (x^2-16)/(x^2-x-6) ?
The inverse of (x^2-16)/(x^2-x-6) is (x+sqrt(25x^2-88x+64))/(2(x-1)),(x-sqrt(25x^2-88x+64))/(2(x-1))