What is the inverse of 2x-0.5x^2-1 ?

The inverse of 2x-0.5x^2-1 is -(-20+sqrt(-200x+200))/(10),-(-20-sqrt(-200x+200))/(10)

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inverse of 2x-0.5x^2-1

inverse

2 x - 0.5 x^{2} - 1

- \frac{- 20 + - 200 x + 200}{10}, - \frac{- 20 - - 200 x + 200}{10}

Solution steps

y = 2 x - 0.5 x^{2} - 1

Replace

x

with

y

x = 2 y - 0.5 y^{2} - 1

Solve for

y, x = 2 y - 0.5 y^{2} - 1

- \frac{- 20 + - 200 x + 200}{10}, - \frac{- 20 - - 200 x + 200}{10}

f (x) = 2 + \frac{3}{x - 4}

\frac{6}{( x ^{2} + 1 )}

f (x) = 3 x - 6 + 11

- 4 + lo g_{5} (x + 5)

f (x) = 4 - x + x - 2

What is the inverse of 2x-0.5x^2-1 ?
The inverse of 2x-0.5x^2-1 is -(-20+sqrt(-200x+200))/(10),-(-20-sqrt(-200x+200))/(10)