What is the inverse of f(x)=\sqrt[3]{x-6}+11 ?

The inverse of f(x)=\sqrt[3]{x-6}+11 is x^3-33x^2+363x-1325

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inverse of f(x)=\sqrt[3]{x-6}+11

inverse

f (x) = 3 x - 6 + 11

x^{3} - 33 x^{2} + 363 x - 1325

Solution steps

y = 3 x - 6 + 11

Replace

x

with

y

x = 3 y - 6 + 11

Solve for

y, x = 3 y - 6 + 11

x^{3} - 33 x^{2} + 363 x - 1325

- 4 + lo g_{5} (x + 5)

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\frac{2 x + 4}{x - 1}

\frac{s + 3}{( s ^{2} - 9 ) ( s + 1 )}

f (x) = - 2 x^{2} + 8 x - 7, x > 2

What is the inverse of f(x)=\sqrt[3]{x-6}+11 ?
The inverse of f(x)=\sqrt[3]{x-6}+11 is x^3-33x^2+363x-1325