What is the inverse of f(x)=(e^{x^2})^{+1} ?

The inverse of f(x)=(e^{x^2})^{+1} is sqrt(ln(x)),-sqrt(ln(x))

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inverse of f(x)=(e^{x^2})^{+1}

inverse

f (x) = (e^{x^{2}})^{+ 1}

ln (x), - ln (x)

Solution steps

y = (e^{x^{2}})^{1}

Replace

x

with

y

x = (e^{y^{2}})^{1}

Solve for

y, x = (e^{y^{2}})^{+ 1}

ln (x), - ln (x)

\frac{2 x ^{2} + 1}{3 x - 5}

\frac{5 x + 5}{8 x + 32}

f (x) = - 2 (x - 2)^{2} - 3

\frac{x - 2}{x + 4}

2^{x} + 5

What is the inverse of f(x)=(e^{x^2})^{+1} ?
The inverse of f(x)=(e^{x^2})^{+1} is sqrt(ln(x)),-sqrt(ln(x))