What is the inverse of f(x)=((2x+1))/(3x-2) ?

The inverse of f(x)=((2x+1))/(3x-2) is (1+2x)/(3x-2)

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inverse of f(x)=((2x+1))/(3x-2)

inverse

f (x) = \frac{( 2 x + 1 )}{3 x - 2}

\frac{1 + 2 x}{3 x - 2}

Solution steps

y = \frac{2 x + 1}{3 x - 2}

Replace

x

with

y

x = \frac{2 y + 1}{3 y - 2}

Solve for

y, x = \frac{2 y + 1}{3 y - 2}

\frac{1 + 2 x}{3 x - 2}

\frac{x}{9 x - 1}

\frac{x ^{2}}{4}

h (x) = \frac{5 x - 3}{7 - 4 x}

f (x) = 4 - x^{2} - 2 x

f (x) = \frac{( \frac{x + 1}{2} )}{2}

What is the inverse of f(x)=((2x+1))/(3x-2) ?
The inverse of f(x)=((2x+1))/(3x-2) is (1+2x)/(3x-2)