What is the inverse of f(x)=\sqrt[3]{8-3x} ?

The inverse of f(x)=\sqrt[3]{8-3x} is -(x^3-8)/3

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inverse of f(x)=\sqrt[3]{8-3x}

inverse

f (x) = 3 8 - 3 x

- \frac{x ^{3} - 8}{3}

Solution steps

y = 3 8 - 3 x

Replace

x

with

y

x = 3 8 - 3 y

Solve for

y, x = 3 8 - 3 y

- \frac{x ^{3} - 8}{3}

- \frac{1}{4} x - 2

x^{2} + x + 3

x^{2} + 4 + 1

f (x) = x^{3 + 8}

f (x) = 100 (\frac{1 - t}{40})^{2}

What is the inverse of f(x)=\sqrt[3]{8-3x} ?
The inverse of f(x)=\sqrt[3]{8-3x} is -(x^3-8)/3