What is the inverse of f(x)=(x-8)^2+7 ?

The inverse of f(x)=(x-8)^2+7 is sqrt(x-7)+8,-sqrt(x-7)+8

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inverse of f(x)=(x-8)^2+7

inverse

f (x) = (x - 8)^{2} + 7

x - 7 + 8, - x - 7 + 8

Solution steps

y = (x - 8)^{2} + 7

Replace

x

with

y

x = (y - 8)^{2} + 7

Solve for

y, x = (y - 8)^{2} + 7

x - 7 + 8, - x - 7 + 8

f (x) = 7 x^{2} + 4, x > 0

\frac{1}{2} x - 4

y = 7 x^{2} + 4 x - 3

- 2 x - 2 + 6

\frac{9 x}{x + 2}

What is the inverse of f(x)=(x-8)^2+7 ?
The inverse of f(x)=(x-8)^2+7 is sqrt(x-7)+8,-sqrt(x-7)+8