What is the inverse of f(x)=x^2-16x+78 ?

The inverse of f(x)=x^2-16x+78 is 8+sqrt(x-14),8-sqrt(x-14)

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inverse of f(x)=x^2-16x+78

inverse

f (x) = x^{2} - 16 x + 78

8 + x - 14, 8 - x - 14

Solution steps

y = x^{2} - 16 x + 78

Replace

x

with

y

x = y^{2} - 16 y + 78

Solve for

y, x = y^{2} - 16 y + 78

8 + x - 14, 8 - x - 14

f (x) = (x - 2)^{2} + 4, x \geq 2

\frac{2 x + 1}{3 - 2 x}

f (x) = 5 x + 13 + 5

6 x

1 - \frac{2}{x}

What is the inverse of f(x)=x^2-16x+78 ?
The inverse of f(x)=x^2-16x+78 is 8+sqrt(x-14),8-sqrt(x-14)