What is the inverse of 2x^2+8x-10 ?

The inverse of 2x^2+8x-10 is (-8+sqrt(8x+144))/4 ,(-8-sqrt(8x+144))/4

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inverse of 2x^2+8x-10

inverse

2 x^{2} + 8 x - 10

\frac{- 8 + 8 x + 144}{4}, \frac{- 8 - 8 x + 144}{4}

Solution steps

y = 2 x^{2} + 8 x - 10

Replace

x

with

y

x = 2 y^{2} + 8 y - 10

Solve for

y, x = 2 y^{2} + 8 y - 10

\frac{- 8 + 8 x + 144}{4}, \frac{- 8 - 8 x + 144}{4}

\frac{5}{s ^{2} - 3 s + 3}

g (s) = 65 t

f (x) = \frac{3}{x - 3} + 1

f (x) = 2 - e^{x + 3}

25200 + 28 b^{2}

What is the inverse of 2x^2+8x-10 ?
The inverse of 2x^2+8x-10 is (-8+sqrt(8x+144))/4 ,(-8-sqrt(8x+144))/4