What is the inverse of f(x)=(x-4)/(2x+1) ?

The inverse of f(x)=(x-4)/(2x+1) is (-4-x)/(2x-1)

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inverse of f(x)=(x-4)/(2x+1)

inverse

f (x) = \frac{x - 4}{2 x + 1}

\frac{- 4 - x}{2 x - 1}

Solution steps

y = \frac{x - 4}{2 x + 1}

Replace

x

with

y

x = \frac{y - 4}{2 y + 1}

Solve for

y, x = \frac{y - 4}{2 y + 1}

\frac{- 4 - x}{2 x - 1}

f (x) = (x^{3} + 1)^{\frac{1}{5}} + 2

f (x) = \frac{4 x - 1}{7 x + 5}

f (x) = \frac{( 5 x + 2 )}{( 3 - x )}

lo g_{x} (2)

f (x) = arccos (\frac{4 - x}{3 + x})

What is the inverse of f(x)=(x-4)/(2x+1) ?
The inverse of f(x)=(x-4)/(2x+1) is (-4-x)/(2x-1)