What is the inverse of f(x)=((8x-2))/(x+5) ?

The inverse of f(x)=((8x-2))/(x+5) is (-2-5x)/(x-8)

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inverse of f(x)=((8x-2))/(x+5)

inverse

f (x) = \frac{( 8 x - 2 )}{x + 5}

\frac{- 2 - 5 x}{x - 8}

Solution steps

y = \frac{8 x - 2}{x + 5}

Replace

x

with

y

x = \frac{8 y - 2}{y + 5}

Solve for

y, x = \frac{8 y - 2}{y + 5}

\frac{- 2 - 5 x}{x - 8}

f (x) = \frac{1}{( x ^{2} - x )}

\frac{1}{ln ( e ^{x} + 1 )}

[\frac{z ^{2}}{( z - 1 ) ( z - 3 )}]

f (x) = (1, 5) (- 3, 2) (8, - 6)

f (x) = \frac{400}{x ^{2}}

What is the inverse of f(x)=((8x-2))/(x+5) ?
The inverse of f(x)=((8x-2))/(x+5) is (-2-5x)/(x-8)