What is the inverse of f(x)=(7x-2)/(5x+1) ?

The inverse of f(x)=(7x-2)/(5x+1) is (-2-x)/(5x-7)

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inverse of f(x)=(7x-2)/(5x+1)

inverse

f (x) = \frac{7 x - 2}{5 x + 1}

\frac{- 2 - x}{5 x - 7}

Solution steps

y = \frac{7 x - 2}{5 x + 1}

Replace

x

with

y

x = \frac{7 y - 2}{5 y + 1}

Solve for

y, x = \frac{7 y - 2}{5 y + 1}

\frac{- 2 - x}{5 x - 7}

f (x) = \frac{( x - 1 )}{( x + 5 )}

f (x) = - 0.5 (e^{2 x} - 1)

f (x) = \frac{7}{x} - 2

4 (x - 7)^{2} + 3, x \leq 7

f (x) = \frac{3 x + 9}{4}

What is the inverse of f(x)=(7x-2)/(5x+1) ?
The inverse of f(x)=(7x-2)/(5x+1) is (-2-x)/(5x-7)