What is the inverse of f(x)=(2x-1)/(3x-2) ?

The inverse of f(x)=(2x-1)/(3x-2) is (-1+2x)/(3x-2)

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inverse of f(x)=(2x-1)/(3x-2)

inverse

f (x) = \frac{2 x - 1}{3 x - 2}

\frac{- 1 + 2 x}{3 x - 2}

Solution steps

y = \frac{2 x - 1}{3 x - 2}

Replace

x

with

y

x = \frac{2 y - 1}{3 y - 2}

Solve for

y, x = \frac{2 y - 1}{3 y - 2}

\frac{- 1 + 2 x}{3 x - 2}

f (x) = 2 x^{2} + 4 x + 2

f (x) = 3 e^{- 2 x}

z \frac{z}{z - 1}

f (x) = \frac{5 x - 2}{2 x + 1}

f (x) = \frac{e ^{x}}{5 + 4 e ^{x}}

What is the inverse of f(x)=(2x-1)/(3x-2) ?
The inverse of f(x)=(2x-1)/(3x-2) is (-1+2x)/(3x-2)