What is the inverse of f(x)=9log_{e}(9x+9) ?

The inverse of f(x)=9log_{e}(9x+9) is (e^{x/9}-9)/9

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inverse of f(x)=9log_{e}(9x+9)

inverse

f (x) = 9 lo g_{e} (9 x + 9)

\frac{e ^{\frac{x}{9}} - 9}{9}

Solution steps

y = 9 lo g_{e} (9 x + 9)

Replace

x

with

y

x = 9 lo g_{e} (9 y + 9)

Solve for

y, x = 9 lo g_{e} (9 y + 9)

\frac{e ^{\frac{x}{9}} - 9}{9}

- \frac{x + 6}{13}

f (x) = \frac{1}{2} (x + 1)^{2}

f (x) = (x - 3)^{2} - 8, x > 3

- 7 x - 4

- 3 - 2 x + 3

What is the inverse of f(x)=9log_{e}(9x+9) ?
The inverse of f(x)=9log_{e}(9x+9) is (e^{x/9}-9)/9