What is the inverse of f(x)=sqrt(x^2-3x-10) ?

The inverse of f(x)=sqrt(x^2-3x-10) is (3+sqrt(4x^2+49))/2 ,(3-sqrt(4x^2+49))/2

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inverse of f(x)=sqrt(x^2-3x-10)

inverse

f (x) = x^{2} - 3 x - 10

\frac{3 + 4 x ^{2} + 49}{2}, \frac{3 - 4 x ^{2} + 49}{2}

Solution steps

y = x^{2} - 3 x - 10

Replace

x

with

y

x = y^{2} - 3 y - 10

Solve for

y, x = y^{2} - 3 y - 10

\frac{3 + 4 x ^{2} + 49}{2}, \frac{3 - 4 x ^{2} + 49}{2}

f (x) = g (x) = 3 x

300 (4^{t})

f (x) = 4 x^{2}, x \geq 0

f (x) = (x - 4)^{2} + 6

What is the inverse of f(x)=sqrt(x^2-3x-10) ?
The inverse of f(x)=sqrt(x^2-3x-10) is (3+sqrt(4x^2+49))/2 ,(3-sqrt(4x^2+49))/2