What is the inverse of (x-3)/(x^2) ?

The inverse of (x-3)/(x^2) is (1+sqrt(1-12x))/(2x),(1-sqrt(1-12x))/(2x)

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inverse of (x-3)/(x^2)

inverse

\frac{x - 3}{x ^{2}}

\frac{1 + 1 - 12 x}{2 x}, \frac{1 - 1 - 12 x}{2 x}

Solution steps

y = \frac{x - 3}{x ^{2}}

Replace

x

with

y

x = \frac{y - 3}{y ^{2}}

Solve for

y, x = \frac{y - 3}{y ^{2}}

\frac{1 + 1 - 12 x}{2 x}, \frac{1 - 1 - 12 x}{2 x}

27.2 x^{- 0.314}

f (x) = \frac{8}{5 + x}

e^{x + 3}

f (x) = - 2 + 3^{x - 1}

f (x) = - (x - 1)^{2} - 1

What is the inverse of (x-3)/(x^2) ?
The inverse of (x-3)/(x^2) is (1+sqrt(1-12x))/(2x),(1-sqrt(1-12x))/(2x)