What is the inverse of 2(x-2)^2-1 ?

The inverse of 2(x-2)^2-1 is sqrt((x+1)/2)+2,-sqrt((x+1)/2)+2

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inverse of 2(x-2)^2-1

inverse

2 (x - 2)^{2} - 1

\frac{x + 1}{2} + 2, - \frac{x + 1}{2} + 2

Solution steps

y = 2 (x - 2)^{2} - 1

Replace

x

with

y

x = 2 (y - 2)^{2} - 1

Solve for

y, x = 2 (y - 2)^{2} - 1

\frac{x + 1}{2} + 2, - \frac{x + 1}{2} + 2

f (x) = \frac{7 x - 1}{2 x + 8}

f (x) = \frac{7 x - 1}{2 x + 6}

f (x) = (x + 4)^{2} - 5

f (x) = 4 x - x^{2} - 3

lo g_{3} (4 x - 1) + 1

What is the inverse of 2(x-2)^2-1 ?
The inverse of 2(x-2)^2-1 is sqrt((x+1)/2)+2,-sqrt((x+1)/2)+2