What is the inverse of f(x)=7x^2+8 ?

The inverse of f(x)=7x^2+8 is sqrt((x-8)/7),-sqrt((x-8)/7)

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inverse of f(x)=7x^2+8

inverse

f (x) = 7 x^{2} + 8

\frac{x - 8}{7}, - \frac{x - 8}{7}

Solution steps

y = 7 x^{2} + 8

Replace

x

with

y

x = 7 y^{2} + 8

Solve for

y, x = 7 y^{2} + 8

\frac{x - 8}{7}, - \frac{x - 8}{7}

1.33

f (8) = 2 x + 9

- 2 (x - 1)^{2} + 3

e^{1 - \frac{x ^{2}}{8}}

e^{- x} + 2

What is the inverse of f(x)=7x^2+8 ?
The inverse of f(x)=7x^2+8 is sqrt((x-8)/7),-sqrt((x-8)/7)