What is the inverse of e^{1-(x^2)/8} ?

The inverse of e^{1-(x^2)/8} is sqrt(-8ln(x)+8),-sqrt(-8ln(x)+8)

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inverse of e^{1-(x^2)/8}

inverse

e^{1 - \frac{x ^{2}}{8}}

- 8 ln (x) + 8, - - 8 ln (x) + 8

Solution steps

y = e^{1 - \frac{x ^{2}}{8}}

Replace

x

with

y

x = e^{1 - \frac{y ^{2}}{8}}

Solve for

y, x = e^{1 - \frac{y ^{2}}{8}}

- 8 ln (x) + 8, - - 8 ln (x) + 8

e^{- x} + 2

3 y + 6

f (x) = - 2 x + 10, x \geq 6

\frac{6}{π} \cdot arcsin (\frac{1}{x})

f (x) = 0.5 x + 0.5

What is the inverse of e^{1-(x^2)/8} ?
The inverse of e^{1-(x^2)/8} is sqrt(-8ln(x)+8),-sqrt(-8ln(x)+8)