What is the inverse of 6/pi*arcsin(1/x) ?

The inverse of 6/pi*arcsin(1/x) is 1/(sin(\frac{xpi){6})}

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inverse of 6/pi*arcsin(1/x)

inverse

\frac{6}{π} \cdot arcsin (\frac{1}{x})

\frac{1}{sin ( \frac{x π}{6} )}

Solution steps

Solve for

arcsin (\frac{1}{x}), y = \frac{6}{π} \cdot arcsin (\frac{1}{x})

arcsin (\frac{1}{x}) = \frac{y π}{6}

arcsin (a) = b \Rightarrow a = sin (b)

\frac{1}{x} = sin (\frac{y π}{6})

Solve for

x, \frac{1}{x} = sin (\frac{y π}{6})

\frac{1}{sin ( \frac{y π}{6} )}

Substitute

y = x

\frac{1}{sin ( \frac{x π}{6} )}

f (x) = 0.5 x + 0.5

- 2 ln (x) + 3

f (x) = 8 3 x + 4 - 6

y = 7 x + 3

\frac{x + 4}{- 4 x + 3}

What is the inverse of 6/pi*arcsin(1/x) ?
The inverse of 6/pi*arcsin(1/x) is 1/(sin(\frac{xpi){6})}