What is the inverse of sqrt(1-y^2) ?

The inverse of sqrt(1-y^2) is sqrt(-y^2+1),-sqrt(-y^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of sqrt(1-y^2)

inverse

1 - y^{2}

- y^{2} + 1, - - y^{2} + 1

Solution steps

y = 1 - y^{2}

Replace

y

with

y

y = 1 - y^{2}

Solve for

y, y = 1 - y^{2}

- y^{2} + 1, - - y^{2} + 1

f (x) = 5 + 2 x - 6

f (x) = \frac{3 x - 1}{5 x + 2}

x^{\frac{3}{7}}

f (x) = 22 x - 14

What is the inverse of sqrt(1-y^2) ?
The inverse of sqrt(1-y^2) is sqrt(-y^2+1),-sqrt(-y^2+1)