What is the inverse of f(x)=f(x)=x^2+2 ?

The inverse of f(x)=f(x)=x^2+2 is sqrt(x-2),-sqrt(x-2)

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inverse of f(x)=f(x)=x^2+2

inverse

f (x) = f (x) = x^{2} + 2

x - 2, - x - 2

Solution steps

y = x^{2} + 2

Replace

x

with

y

x = y^{2} + 2

Solve for

y, x = y^{2} + 2

x - 2, - x - 2

f (x) = \frac{3 - 4 x}{5 x + 1}

\frac{2 s - 8}{s ^{2} - 4 s - 4}

y = - 4.9 (x + 3)^{2} + 45.8

f (x) = \frac{x + 6}{2}

f (x) = - \frac{( x + 1 )}{2}

What is the inverse of f(x)=f(x)=x^2+2 ?
The inverse of f(x)=f(x)=x^2+2 is sqrt(x-2),-sqrt(x-2)