What is the inverse of f(x)=sqrt(x+1)+x ?

The inverse of f(x)=sqrt(x+1)+x is (2x+1+sqrt(4x+5))/2 ,(2x+1-sqrt(4x+5))/2

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inverse of f(x)=sqrt(x+1)+x

inverse

f (x) = x + 1 + x

\frac{2 x + 1 + 4 x + 5}{2}, \frac{2 x + 1 - 4 x + 5}{2}

Solution steps

y = x + 1 + x

Replace

x

with

y

x = y + 1 + y

Solve for

y, x = y + 1 + y

\frac{2 x + 1 + 4 x + 5}{2}, \frac{2 x + 1 - 4 x + 5}{2}

f (x) = x - 5 + 4

f (x) = 4 (x - 3)^{5} + 21

cos (π x - 2) - 1

f (x) = lo g_{e} (x - 2)

5 + 2 sin (\frac{x - 1}{x + 1})

What is the inverse of f(x)=sqrt(x+1)+x ?
The inverse of f(x)=sqrt(x+1)+x is (2x+1+sqrt(4x+5))/2 ,(2x+1-sqrt(4x+5))/2