What is the inverse of 1/(sqrt(9-x^2)) ?

The inverse of 1/(sqrt(9-x^2)) is sqrt(-(1-9x^2)/(x^2)),-sqrt(-(1-9x^2)/(x^2))

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inverse of 1/(sqrt(9-x^2))

inverse

\frac{1}{9 - x ^{2}}

- \frac{1 - 9 x ^{2}}{x ^{2}}, - - \frac{1 - 9 x ^{2}}{x ^{2}}

Solution steps

y = \frac{1}{9 - x ^{2}}

Replace

x

with

y

x = \frac{1}{9 - y ^{2}}

Solve for

y, x = \frac{1}{9 - y ^{2}}

- \frac{1 - 9 x ^{2}}{x ^{2}}, - - \frac{1 - 9 x ^{2}}{x ^{2}}

f (x) = 2 x^{2} - 5 x

f (x) = - 4 x - 2

f (x) = \frac{3}{3 x + 4}

f (x) = \frac{3}{3 x + 2}

f (x) = 4 (x + 3) - 2

What is the inverse of 1/(sqrt(9-x^2)) ?
The inverse of 1/(sqrt(9-x^2)) is sqrt(-(1-9x^2)/(x^2)),-sqrt(-(1-9x^2)/(x^2))