What is the inverse of f(x)=(2x^3+1)/6 ?

The inverse of f(x)=(2x^3+1)/6 is cube root of (6x-1)/2

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inverse of f(x)=(2x^3+1)/6

inverse

f (x) = \frac{2 x ^{3} + 1}{6}

Solution steps

y = \frac{2 x ^{3} + 1}{6}

Replace

x

with

y

x = \frac{2 y ^{3} + 1}{6}

Solve for

y, x = \frac{2 y ^{3} + 1}{6}

f (x) = 4 x^{2} + 6 x + 2

f (x) = \frac{3 x}{4}

f (x) = \frac{5 - x}{3 x - 2}

f (x) = \frac{- 5}{2 x + 2}

What is the inverse of f(x)=(2x^3+1)/6 ?
The inverse of f(x)=(2x^3+1)/6 is cube root of (6x-1)/2