What is the inverse of f(x)=\sqrt[3]{(x^2+1)-5} ?

The inverse of f(x)=\sqrt[3]{(x^2+1)-5} is sqrt(x^3+4),-sqrt(x^3+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{(x^2+1)-5}

inverse

x^{3} + 4, - x^{3} + 4

Solution steps

Replace

x

with

y

Solve for

x^{3} + 4, - x^{3} + 4

f (x) = \frac{5 x}{9 x - 8}

f (x) = \frac{1 - 2 x}{3 - x}

\frac{1}{s ( s + a )}

f (x) = 3 x^{2} - 3 x - 18

cos (- 0.15106)

What is the inverse of f(x)=\sqrt[3]{(x^2+1)-5} ?
The inverse of f(x)=\sqrt[3]{(x^2+1)-5} is sqrt(x^3+4),-sqrt(x^3+4)