What is the inverse of f(x)=(1-2x)/(3-x) ?

The inverse of f(x)=(1-2x)/(3-x) is (1-3x)/(-x+2)

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inverse of f(x)=(1-2x)/(3-x)

inverse

f (x) = \frac{1 - 2 x}{3 - x}

\frac{1 - 3 x}{- x + 2}

Solution steps

y = \frac{1 - 2 x}{3 - x}

Replace

x

with

y

x = \frac{1 - 2 y}{3 - y}

Solve for

y, x = \frac{1 - 2 y}{3 - y}

\frac{1 - 3 x}{- x + 2}

\frac{1}{s ( s + a )}

f (x) = 3 x^{2} - 3 x - 18

cos (- 0.15106)

f (x) = \frac{8}{3 + x ^{2}}

f (x) = - ln (x + 2) + 1

What is the inverse of f(x)=(1-2x)/(3-x) ?
The inverse of f(x)=(1-2x)/(3-x) is (1-3x)/(-x+2)