What is the inverse of 1/((sqrt(x^2+4))) ?

The inverse of 1/((sqrt(x^2+4))) is (sqrt(1-4x^2))/x ,-(sqrt(1-4x^2))/x

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inverse of 1/((sqrt(x^2+4)))

inverse

\frac{1}{( x ^{2} + 4 )}

\frac{1 - 4 x ^{2}}{x}, - \frac{1 - 4 x ^{2}}{x}

Solution steps

y = \frac{1}{x ^{2} + 4}

Replace

x

with

y

x = \frac{1}{y ^{2} + 4}

Solve for

y, x = \frac{1}{y ^{2} + 4}

\frac{1 - 4 x ^{2}}{x}, - \frac{1 - 4 x ^{2}}{x}

y = 2 x + 7 + 5

f (x) = - 8 x - 8

x + a

f (x) = 6 y = (x - 4)^{2} - \frac{2}{3} + 12

sin (x)

What is the inverse of 1/((sqrt(x^2+4))) ?
The inverse of 1/((sqrt(x^2+4))) is (sqrt(1-4x^2))/x ,-(sqrt(1-4x^2))/x