What is the inverse of 5+\sqrt[3]{4/x} ?

The inverse of 5+\sqrt[3]{4/x} is 4/(x^3-15x^2+75x-125)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 5+\sqrt[3]{4/x}

inverse

5 + 3 \frac{4}{x}

\frac{4}{x ^{3} - 15 x ^{2} + 75 x - 125}

Solution steps

y = 5 + 3 \frac{4}{x}

Replace

x

with

y

x = 5 + 3 \frac{4}{y}

Solve for

y, x = 5 + 3 \frac{4}{y}

\frac{4}{x ^{3} - 15 x ^{2} + 75 x - 125}

f (x) = 4 - 3 cos (3 x - \frac{π}{3})

f (x) = (1 - x^{3})^{\frac{1}{3}}

7 - 9 x

f (x) = - 5 cos (3 x)

\frac{3 + 5 x}{x}

What is the inverse of 5+\sqrt[3]{4/x} ?
The inverse of 5+\sqrt[3]{4/x} is 4/(x^3-15x^2+75x-125)