What is the inverse of f(x)=sqrt(x^2-5)+2 ?

The inverse of f(x)=sqrt(x^2-5)+2 is sqrt(x^2-4x+9),-sqrt(x^2-4x+9)

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inverse of f(x)=sqrt(x^2-5)+2

inverse

f (x) = x^{2} - 5 + 2

x^{2} - 4 x + 9, - x^{2} - 4 x + 9

Solution steps

y = x^{2} - 5 + 2

Replace

x

with

y

x = y^{2} - 5 + 2

Solve for

y, x = y^{2} - 5 + 2

x^{2} - 4 x + 9, - x^{2} - 4 x + 9

f (x) = - (x - 5) - 2

f (x) = 3 4 - x

(x + 4)^{2} - 1

f (x) = 3 4 x + 6

2 x^{2} + 8 x - 8

What is the inverse of f(x)=sqrt(x^2-5)+2 ?
The inverse of f(x)=sqrt(x^2-5)+2 is sqrt(x^2-4x+9),-sqrt(x^2-4x+9)