What is the inverse of f(x)=\sqrt[3]{4x+6} ?

The inverse of f(x)=\sqrt[3]{4x+6} is (x^3-6)/4

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inverse of f(x)=\sqrt[3]{4x+6}

inverse

f (x) = 3 4 x + 6

\frac{x ^{3} - 6}{4}

Solution steps

y = 3 4 x + 6

Replace

x

with

y

x = 3 4 y + 6

Solve for

y, x = 3 4 y + 6

\frac{x ^{3} - 6}{4}

2 x^{2} + 8 x - 8

\frac{6 s + 16}{s ^{2} + 2 s + 5}

x^{2} - 2, x \geq 0

f (x) = - \frac{13}{4} (\frac{7}{2})^{x + 11} - 5

2^{x} + 1

What is the inverse of f(x)=\sqrt[3]{4x+6} ?
The inverse of f(x)=\sqrt[3]{4x+6} is (x^3-6)/4