What is the inverse of (6s+16)/(s^2+2s+5) ?

The inverse of (6s+16)/(s^2+2s+5) is (-s+3+sqrt(-4s^2+10s+9))/s ,(-s+3-sqrt(-4s^2+10s+9))/s

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inverse of (6s+16)/(s^2+2s+5)

inverse

\frac{6 s + 16}{s ^{2} + 2 s + 5}

\frac{- s + 3 + - 4 s ^{2} + 10 s + 9}{s}, \frac{- s + 3 - - 4 s ^{2} + 10 s + 9}{s}

Solution steps

y = \frac{6 s + 16}{s ^{2} + 2 s + 5}

Replace

s

with

y

s = \frac{6 y + 16}{y ^{2} + 2 y + 5}

Solve for

y, s = \frac{6 y + 16}{y ^{2} + 2 y + 5}

\frac{- s + 3 + - 4 s ^{2} + 10 s + 9}{s}, \frac{- s + 3 - - 4 s ^{2} + 10 s + 9}{s}

x^{2} - 2, x \geq 0

f (x) = - \frac{13}{4} (\frac{7}{2})^{x + 11} - 5

2^{x} + 1

f (x) = \frac{x + 9}{x + 3}

f (x) = \frac{e ^{x}}{5 + e ^{2}}

What is the inverse of (6s+16)/(s^2+2s+5) ?
The inverse of (6s+16)/(s^2+2s+5) is (-s+3+sqrt(-4s^2+10s+9))/s ,(-s+3-sqrt(-4s^2+10s+9))/s