What is the inverse of f(x)=-2(x+1)^2+3 ?

The inverse of f(x)=-2(x+1)^2+3 is sqrt(-(x-3)/2)-1,-sqrt(-(x-3)/2)-1

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inverse of f(x)=-2(x+1)^2+3

inverse

f (x) = - 2 (x + 1)^{2} + 3

- \frac{x - 3}{2} - 1, - - \frac{x - 3}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} + 3

Replace

x

with

y

x = - 2 (y + 1)^{2} + 3

Solve for

y, x = - 2 (y + 1)^{2} + 3

- \frac{x - 3}{2} - 1, - - \frac{x - 3}{2} - 1

tan (\frac{5}{12})

y = lo g_{10} (x) - 5

f (x) = \frac{4 x + 1}{x - 2}

f (x) = - 2 (x + 1)^{2} - 5

f (x) = \frac{9 x}{4 x - 7}

What is the inverse of f(x)=-2(x+1)^2+3 ?
The inverse of f(x)=-2(x+1)^2+3 is sqrt(-(x-3)/2)-1,-sqrt(-(x-3)/2)-1