What is the inverse of f(x)=9x^2-7 ?

The inverse of f(x)=9x^2-7 is (sqrt(x+7))/3 ,-(sqrt(x+7))/3

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inverse of f(x)=9x^2-7

inverse

f (x) = 9 x^{2} - 7

\frac{x + 7}{3}, - \frac{x + 7}{3}

Solution steps

y = 9 x^{2} - 7

Replace

x

with

y

x = 9 y^{2} - 7

Solve for

y, x = 9 y^{2} - 7

\frac{x + 7}{3}, - \frac{x + 7}{3}

f (x) = 9 x^{2} - 8

f (x) = 9 x^{2} + 2

- 60 (x - 3)^{2} - 50

h (x) = \frac{5 x - 3}{2 x + 1}

f (x) = 2 - \frac{3 x}{2}

What is the inverse of f(x)=9x^2-7 ?
The inverse of f(x)=9x^2-7 is (sqrt(x+7))/3 ,-(sqrt(x+7))/3