What is the inverse of f(x)=x^2-x+2 ?

The inverse of f(x)=x^2-x+2 is (1+sqrt(4x-7))/2 ,(1-sqrt(4x-7))/2

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inverse of f(x)=x^2-x+2

inverse

f (x) = x^{2} - x + 2

\frac{1 + 4 x - 7}{2}, \frac{1 - 4 x - 7}{2}

Solution steps

y = x^{2} - x + 2

Replace

x

with

y

x = y^{2} - y + 2

Solve for

y, x = y^{2} - y + 2

\frac{1 + 4 x - 7}{2}, \frac{1 - 4 x - 7}{2}

f (x) = e^{a r c t a n (x^{2} + 1)}

f (x) = \frac{- 4}{2 x + 3}

f (x) = 3 cos (\frac{π}{3} (x - 5)) + 2

f (x) = 2 x^{2} + 4 x - 7

f (x) = \frac{1}{2 - sin ( 3 x )}

What is the inverse of f(x)=x^2-x+2 ?
The inverse of f(x)=x^2-x+2 is (1+sqrt(4x-7))/2 ,(1-sqrt(4x-7))/2