What is the inverse of f(x)=3x^2+25x+28 ?

The inverse of f(x)=3x^2+25x+28 is (-25+sqrt(12x+289))/6 ,(-25-sqrt(12x+289))/6

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inverse of f(x)=3x^2+25x+28

inverse

f (x) = 3 x^{2} + 25 x + 28

\frac{- 25 + 12 x + 289}{6}, \frac{- 25 - 12 x + 289}{6}

Solution steps

y = 3 x^{2} + 25 x + 28

Replace

x

with

y

x = 3 y^{2} + 25 y + 28

Solve for

y, x = 3 y^{2} + 25 y + 28

\frac{- 25 + 12 x + 289}{6}, \frac{- 25 - 12 x + 289}{6}

f (x) = \frac{( x + 1 )}{2}

f (x) = (x + 4) = x^{2}

y = \frac{3}{x - 5} + 2

f (x) = 7 \frac{( x ^{\frac{1}{3}} )}{6} + 5

7 x^{2} - 10

What is the inverse of f(x)=3x^2+25x+28 ?
The inverse of f(x)=3x^2+25x+28 is (-25+sqrt(12x+289))/6 ,(-25-sqrt(12x+289))/6