What is the inverse of f(x)=7(((x^{1/3}))/6+5) ?

The inverse of f(x)=7(((x^{1/3}))/6+5) is (216x^3}{343}-(3240x^2)/(49)+\frac{16200x)/7-27000

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inverse of f(x)=7(((x^{1/3}))/6+5)

inverse

f (x) = 7 \frac{( x ^{\frac{1}{3}} )}{6} + 5

\frac{216 x ^{3}}{343} - \frac{3240 x ^{2}}{49} + \frac{16200 x}{7} - 27000

Solution steps

y = 7 (\frac{x ^{\frac{1}{3}}}{6} + 5)

Replace

x

with

y

x = 7 (\frac{y ^{\frac{1}{3}}}{6} + 5)

Solve for

y, x = 7 (\frac{y ^{\frac{1}{3}}}{6} + 5)

\frac{216 x ^{3}}{343} - \frac{3240 x ^{2}}{49} + \frac{16200 x}{7} - 27000

7 x^{2} - 10

f (x) = 1 + x^{- 1}

g (x) = 1 - \frac{2 - x}{3}

f (x) = \frac{8 x}{9 x - 4}

\frac{2 s + 5}{( s + 1 ) ( s - 2 )}

What is the inverse of f(x)=7(((x^{1/3}))/6+5) ?
The inverse of f(x)=7(((x^{1/3}))/6+5) is (216x^3}{343}-(3240x^2)/(49)+\frac{16200x)/7-27000