What is the inverse of f(x)=4(x+1)^2 ?

The inverse of f(x)=4(x+1)^2 is (sqrt(x))/2-1,-(sqrt(x))/2-1

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inverse of f(x)=4(x+1)^2

inverse

f (x) = 4 (x + 1)^{2}

\frac{x}{2} - 1, - \frac{x}{2} - 1

Solution steps

y = 4 (x + 1)^{2}

Replace

x

with

y

x = 4 (y + 1)^{2}

Solve for

y, x = 4 (y + 1)^{2}

\frac{x}{2} - 1, - \frac{x}{2} - 1

f (x) = 4 x^{2} - 24 x + 7

h (x) = \frac{x - 6}{7 x + 3}

arctan (\frac{x}{4})

21

f (x) = 5 3 x - 1

What is the inverse of f(x)=4(x+1)^2 ?
The inverse of f(x)=4(x+1)^2 is (sqrt(x))/2-1,-(sqrt(x))/2-1