What is the inverse of f(x)=x^2+x+5 ?

The inverse of f(x)=x^2+x+5 is (-1+sqrt(4x-19))/2 ,(-1-sqrt(4x-19))/2

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inverse of f(x)=x^2+x+5

inverse

f (x) = x^{2} + x + 5

\frac{- 1 + 4 x - 19}{2}, \frac{- 1 - 4 x - 19}{2}

Solution steps

y = x^{2} + x + 5

Replace

x

with

y

x = y^{2} + y + 5

Solve for

y, x = y^{2} + y + 5

\frac{- 1 + 4 x - 19}{2}, \frac{- 1 - 4 x - 19}{2}

f (x) = 3 3 4 x - 3 + 2

f (x) = - x - 2, 2 \leq x \leq 6

(y - 1)^{2}

f (x) = ln (6 - 2 x)

f (x) = x^{2} - 8 b x

What is the inverse of f(x)=x^2+x+5 ?
The inverse of f(x)=x^2+x+5 is (-1+sqrt(4x-19))/2 ,(-1-sqrt(4x-19))/2