What is the inverse of f(x)=11x^2+7 ?

The inverse of f(x)=11x^2+7 is sqrt((x-7)/(11)),-sqrt((x-7)/(11))

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inverse of f(x)=11x^2+7

inverse

f (x) = 11 x^{2} + 7

\frac{x - 7}{11}, - \frac{x - 7}{11}

Solution steps

y = 11 x^{2} + 7

Replace

x

with

y

x = 11 y^{2} + 7

Solve for

y, x = 11 y^{2} + 7

\frac{x - 7}{11}, - \frac{x - 7}{11}

4 - x^{4}

y = \frac{3 + 10 x}{5 x - 4}

y = 1 - \frac{1}{2 ^{\frac{x}{c}}}

f (x) = \frac{3}{- x + 1}

f (x) = (\frac{1}{2})^{x} + 1, x < 0

What is the inverse of f(x)=11x^2+7 ?
The inverse of f(x)=11x^2+7 is sqrt((x-7)/(11)),-sqrt((x-7)/(11))