What is the inverse of f(x)=(x-1)=5-3x^2x-3 ?

The inverse of f(x)=(x-1)=5-3x^2x-3 is -\sqrt[3]{(x-2)/3}

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inverse of f(x)=(x-1)=5-3x^2x-3

inverse

f (x) = (x - 1) = 5 - 3 x^{2} x - 3

Solution steps

y = 5 - 3 x^{2} x - 3

Replace

x

with

y

x = 5 - 3 y^{2} y - 3

Solve for

y, x = 5 - 3 y^{2} y - 3

g (x) = \frac{100}{x - 12} + 8

2 - 3 cos (2 x)

\frac{4 x + 3}{2 - x}

f (x) = - x - 7

y = ln (x - 1) - ln (2 x + 1)

What is the inverse of f(x)=(x-1)=5-3x^2x-3 ?
The inverse of f(x)=(x-1)=5-3x^2x-3 is -\sqrt[3]{(x-2)/3}