What is the inverse of f(x)=log_{2}(x+1)-3 ?

The inverse of f(x)=log_{2}(x+1)-3 is 2^{x+3}-1

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inverse of f(x)=log_{2}(x+1)-3

inverse

f (x) = lo g_{2} (x + 1) - 3

2^{x + 3} - 1

Solution steps

y = lo g_{2} (x + 1) - 3

Replace

x

with

y

x = lo g_{2} (y + 1) - 3

Solve for

y, x = lo g_{2} (y + 1) - 3

2^{x + 3} - 1

3 x^{2} - x + 5

f (x) = lo g_{2} (x + 1) - 2

f (x) = 4 (1 - x^{2})

y = 3 \cdot (2^{4 x - 5})

f (x) = 2 0.5 x + 1 + 2

What is the inverse of f(x)=log_{2}(x+1)-3 ?
The inverse of f(x)=log_{2}(x+1)-3 is 2^{x+3}-1