What is the inverse of f(x)=(5x)/(sqrt(5x^2+1)) ?

The inverse of f(x)=(5x)/(sqrt(5x^2+1)) is sqrt(-(x^2)/(5(x^2-5))),-sqrt(-(x^2)/(5(x^2-5)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(5x)/(sqrt(5x^2+1))

inverse

f (x) = \frac{5 x}{5 x ^{2} + 1}

- \frac{x ^{2}}{5 ( x ^{2} - 5 )}, - - \frac{x ^{2}}{5 ( x ^{2} - 5 )}

Solution steps

y = \frac{5 x}{5 x ^{2} + 1}

Replace

x

with

y

x = \frac{5 y}{5 y ^{2} + 1}

Solve for

y, x = \frac{5 y}{5 y ^{2} + 1}

- \frac{x ^{2}}{5 ( x ^{2} - 5 )}, - - \frac{x ^{2}}{5 ( x ^{2} - 5 )}

f (x) = 0. 5^{x} + 1

f (x) = \frac{3 x + 4}{4 x + 5}

f (x) = (x - 4)^{2}, (4, \infty)

tan (0.6546)

y = \frac{x}{5 x - 8}

What is the inverse of f(x)=(5x)/(sqrt(5x^2+1)) ?
The inverse of f(x)=(5x)/(sqrt(5x^2+1)) is sqrt(-(x^2)/(5(x^2-5))),-sqrt(-(x^2)/(5(x^2-5)))