What is the inverse of f(x)=(x-4)^2,(4,infinity) ?

The inverse of f(x)=(x-4)^2,(4,infinity) is sqrt(x)+4,-sqrt(x)+4

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inverse of f(x)=(x-4)^2,(4,infinity)

inverse

f (x) = (x - 4)^{2}, (4, \infty)

x + 4, - x + 4

Solution steps

y = (x - 4)^{2}

Replace

x

with

y

x = (y - 4)^{2}

Solve for

y, x = (y - 4)^{2}

x + 4, - x + 4

tan (0.6546)

y = \frac{x}{5 x - 8}

f (x) = \frac{3 x - 2}{2 x + 4}

y = \frac{1}{1 - e ^{\frac{- x}{2}}}

ln (1 + x^{2})

What is the inverse of f(x)=(x-4)^2,(4,infinity) ?
The inverse of f(x)=(x-4)^2,(4,infinity) is sqrt(x)+4,-sqrt(x)+4