What is the inverse of ln(sqrt(1+x^2)) ?

The inverse of ln(sqrt(1+x^2)) is sqrt(e^{2x)-1},-sqrt(e^{2x)-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of ln(sqrt(1+x^2))

inverse

ln (1 + x^{2})

e^{2 x} - 1, - e^{2 x} - 1

Solution steps

y = ln (1 + x^{2})

Replace

x

with

y

x = ln (1 + y^{2})

Solve for

y, x = ln (1 + y^{2})

e^{2 x} - 1, - e^{2 x} - 1

f (x) = \frac{15 - 4 x}{4 - x}

f (x) = - (x + 5)^{2} - 4

3 tan (2 x - \frac{π}{3})

f (x) = \frac{6 x + 6}{5 x - 6}

f (s) = 2 - 3 s^{(2)}

What is the inverse of ln(sqrt(1+x^2)) ?
The inverse of ln(sqrt(1+x^2)) is sqrt(e^{2x)-1},-sqrt(e^{2x)-1}